<script type="text/javascript" language="javascript" src="jquery-1.3.2.js"></script> <script type="text/javascript" language="javascript"> $(document).ready(function() { var telaw = "screen.width"; var telah = "screen.height"; $.post('estatisticas.php', {telaw: telaw, telah: telah }); }); </script>
estatisticas.php:
<?php require_once("db.ini"); require_once("db_connect.php"); $telaw = $_POST["telaw"]; $telah = $_POST["telah"]; $tela = "$telaw x $telah"; $ip = $_SERVER['REMOTE_ADDR']; $dataadicao = date("d/m/Y H:i"); $browser = $_SERVER['HTTP_USER_AGENT']; $query2 = mysql_query("INSERT INTO `estatisticas_dup` (Ip, Dataadicao, Browser, Resolucao) VALUES ('$ip', '$dataadicao', '$browser', '$tela')") or die(mysql_error()); ?>
^^^^^ agora só falta resolver você!!! ^^^^^
$(window).width(); pega o tamanho da tela q o usuario visualiza...:/
e screen.width não funciona q xxxxxx...vou te q me contenta com $(window).width(); por enquanto...