<script type="text/javascript" language="javascript" src="jquery-1.3.2.js"></script>
<script type="text/javascript" language="javascript">
$(document).ready(function() {
var telaw = "screen.width";
var telah = "screen.height";
$.post('estatisticas.php', {telaw: telaw, telah: telah });
});
</script>
estatisticas.php:
<?php
require_once("db.ini");
require_once("db_connect.php");
$telaw = $_POST["telaw"];
$telah = $_POST["telah"];
$tela = "$telaw x $telah";
$ip = $_SERVER['REMOTE_ADDR'];
$dataadicao = date("d/m/Y H:i");
$browser = $_SERVER['HTTP_USER_AGENT'];
$query2 = mysql_query("INSERT INTO `estatisticas_dup` (Ip, Dataadicao, Browser, Resolucao) VALUES ('$ip', '$dataadicao', '$browser', '$tela')") or die(mysql_error());
?>
^^^^^ agora só falta resolver você!!! ^^^^^
$(window).width(); pega o tamanho da tela q o usuario visualiza...:/
e screen.width não funciona q xxxxxx...vou te q me contenta com $(window).width(); por enquanto...










